Vijay Khatri wrote:
Thanks Valery,
I have MathCad 15, also wt = 2*pi*60.*t
Will this work in MathCad 15.
Sure. Valery simply used a new variable and named it wt. This is not the product of w and t!
What kind of values are the limits 0 and 3 of your integral? With Valery's approach they are unitless wt values and correspond to t=0 and t=3/w.
If the limits are time values, probably seconds, you would have to replace d(w*t) by w*dt because of 
