Doesn't this mean you are dealing with an anti-ferrimagnet (as opposed to a ferrimagnet)?!!
No
both, antiferromagnets and ferrimagnets, consist of at least two magnetic sublattices whose magnetic moments are antiparallel to each other. The difference between the two is that in the former the moments are equal in absolute value, whereas in the latter they are now. In our case, MEr = 9 and MCo = 5 so we have a ferrimagnet
2. I was puzzled by why the B=0 value of magnetization found by Mathcad is 0, not 4. It seems this is a numerical problem. If you set the initial guess value of phi to -pi/2 you do get 4 for the magnetization at B = 0.
This is exactly what I thought too. Luckily the problem is easily amended.
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Re: Mathcad to calculate magnetization
both, antiferromagnets and ferrimagnets, consist of at least two magnetic sublattices whose magnetic moments are antiparallel to each other. The difference between the two is that in the former the moments are equal in absolute value, whereas in the latter they are now. In our case, MEr = 9 and MCo = 5 so we have a ferrimagnet ↧